42. Solution to Chemistry Problem
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42. Solution to Chemistry Problem
3. Calculate graphically the activation energy and pre-exponential factor (A) from the values of the rate constants k1 and k2 at temperatures T1 and T2; write down the dependence of the rate constant on temperature in analytical form: lnk = f (T); calculate the rate constant k3 at temperature T3 for the reaction of your variant (Table 4.7, 4.8)
Variant 3
Reaction T1K, k1 T2,K k2 T3,K
C6H5CH2Br C2H5OH →C6H5CH2OC2H5 HBr 298 1.44 l/(mol*min) 338 2.01 l/(mol*min) 318
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