17. Solution to Chemistry Problem
17. The enthalpy of dissociation of calcium carbonate at 900 C and a pressure of 1 atm is 178.0 kJ*mol-1. Derive the equation for the dependence of the enthalpy of reaction on temperature and calculate the amount of heat absorbed during the decomposition of 1 kg of calcium carbonate at 1000 C and 1 atm if the molar heat capacities are given (in J * mol-1 * K-1)
CpCaCO3(s) = 104.5 21.92 * 10-3T - 25.94 * 105T-2 J / mol * deg,
CpCaO(s) = 49.63 4.52 * 10-3T - 6.95 * 105T-2 J / mol * deg,
CpCO2(g) = 44.14 9.04 * 10-3T - 8.53 * 105T-2 J / mol * deg,
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