08. Solving a chemistry problem
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08. Solving a chemistry problem
1. Equivalent electrical conductivity of 1.59 ⋅10-4 M acetic acid at 25°C λ = 12.77 S⋅cm2/mol-equiv. Calculate the dissociation constant K and the specific electrical conductivity of the solution (S⋅cm-1), if the ion mobility λ0H = 349.8 S⋅cm2/mol-equiv. and λ0CH3COO– = 40.9 S⋅cm2/mol-eq.
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