42. Solving a chemistry problem

42. Solving a chemistry problem

17. The rate of consumption of individual substance A obeys the equation
-d[A]/dt= k[A]3. At T1 = 333K k = 4.20 * 10-6 (concentration of substance A is expressed in mm Hg), and at T2 = 473K k = 1.4 * 10-4 (concentration is expressed in mm Hg) . Calculate the activation energy and the Arrhenius factor (pre-exponential factor), the constants k at 333 and 473 K, if the concentration of substance A is expressed in mol/l. Calculate the activation energy and the pre-exponential factor if the reaction rate is expressed in mol/(l*s). Explain whether the given activation energy is the true activation energy of the reaction.

Additional information:

If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.