43. Solving a chemistry problem
- Price in currencies:
- 1.17 $ · 111 RUB · 0.99 €
- Category:
- Coursework
- Item:
- 364.rar (15.23 KB)
- Uploaded:
- 17.02.2023 0:03:42
- Sales:
- 0
- Refunds:
- 0
- Seller:
- Derkach · about the seller and their products
DESCRIPTION
43. Solving a chemistry problem
364. The reaction is expressed by the schemes:
Br2 HNO2 H2O = HNO3 HBr,
MnO2 O2 KOH = KMnO4 H2O.
Write electronic equations. Arrange the coefficients in the reaction equations. For each reaction, indicate which substance is the oxidizing agent, which is the reducing agent; which substance is oxidized and which is reduced.
Additional information:
If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.
REVIEWS
Reviews: (0)
No customer reviews yet.
