59. Solving a chemistry problem

Price in currencies:
1.15 $ · 112 RUB · 0.96 €
Category:
Price:
1.15 $
Item:
7.rar (6.04 KB)
Uploaded:
12.01.2023 3:14:36
Sales:
0
Refunds:
0
1.15 $

You will choose the payment method — bank card, cryptocurrency, WebMoney, Alipay, PIX, UPI and others — on the next step. See «Payment methods» for details.

59. Solving a chemistry problem

7. Determine the equivalent of the underlined compounds:
2KMnO4 16HCl = 2MnCl2 5Cl2 2KCl 8H2O

Additional information:

If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.

Reviews: (0)

No customer reviews yet.

More in «Coursework»

All items in «Coursework» →