80. Solving a chemistry problem

80. Solving a chemistry problem

4. The resistivity of a saturated solution of sparingly soluble salt A at 298 K is equal to ρ. The specific resistance of water at the same temperature is ρ H2O = 1 • 104 Ohm • m. Calculate: 1) the solubility of salt A in pure water; 2) the product of the solubility of substance A, assuming that the activity coefficients of ions γ± = 1 (solutions are highly diluted); 3) the solubility of substance A in a solution containing 0.01 mol of substance B; 4) the solubility of substance A in a solution containing 0.01 mol of substance C. Substances A, B, C are completely dissociated.
N option ρ • 10-4, Ohm·m Substance А В С
4 0.33 BaSO4 Na2SO4 KBr

Additional information:

If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.