86. Solving a chemistry problem

86. Solving a chemistry problem

21. The heat of combustion of sucrose under standard conditions is -5645 kJ / mol. Change in the isobaric potential of the reaction for the formation of sucrose
12C(t) 11H2(g) 5.5O2(g)=C12H22O11(t) equals -1555.5 kJ.
Determine the change in the entropy of the reaction.

Additional information:

If you do not open the file - install the RAR archiver. Inside the archive you will find a solution in Word format.