107. Solving a chemistry problem
Calculate the weighed portion of potassium permanganate (M.w. = 158.03 g/mol) to prepare two liters of a titrated 0.1 mol/l solution (UC = 1/5 KMnO4) solution. How to bring the value of K to normal if the correction factor of the prepared solution of potassium permanganate turned out to be 1.06?
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