113. Solving a chemistry problem

113. Solving a chemistry problem

The oxidation of hydrocarbon (RH) proceeds in the general case according to the following scheme:
Initiation RH → R* H*
Chain development R* O2 → RO2
RO2 RO2 → products.
a) graphically and analytically calculate the rate constant of the initiation reaction from tabular data:
[RH], mol/l 10 8.99 6.08 5.28 3.45 2.25 1.18
τ , s 0 5 10 30 50 70 100
b) Using the temperature dependence of the rate constant
t0C 496 441 394 352 315 283
kspeed 464 245 137 73.7 41.9 22.2
Determine the activation energy graphically.

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