121. Solving a chemistry problem
8. Calculate the activity coefficient of silver in silver amalgam with the mole fraction xAg=0.5 if the EMF element
Ag, Hg | AgNO3(aq) | Hg, Ag
xAg=0.5 aAg(Hg)=0.0005
at 298K is 0.156V. Arrange the signs of the electrodes in the element. Answer: 0.436V
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