138. Solving a chemistry problem
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138. Solving a chemistry problem
73. How much do you need to add a solution of KMnO4 with W (KMnO4) = 4.4% to 4850 cm3 of a solution with C (1/5 KMnO4) = 0.1000 mol / dm3 and a correction factor F = 0.9823 to get exactly C ( 1/5 KMnO4) = 0.1000 mol / dm3.
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