143. Solving a chemistry problem
6.37. Using the benzene adsorption isotherm, determine the specific surface area of the adsorbent (Т = 293 K, S0 = 49 * 10–20 m2). The volume of adsorbed gas is reduced to normal conditions:
P / Ps 0.10 0.15 0.20 0.25 0.30 0.36
A * 102, m3 / kg 0.80 1.09 1.27 1.45 1.60 1.79
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