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Solving a problem in physics section 68 point 48 electr
48. Find the cross-sectional area of the silver conductor if the speed of the ordered movement of electrons in it is 0.25 μm / s at a current strength of 20 A and the concentration of conduction electrons is 5 ∙ 1028 m − 3
Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)
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Discount for regular customers! If the total of your purchases from the seller
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