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Solving a problem in physics section 68 point 47 electr
47. Determine the cross-sectional area S of the conductor if, at a current strength of I = 2.0 A, the average velocity of the ordered movement of conduction electrons in it is <υ> = 0.25 mm / s, and their concentration is n = 3.0 ∙ 1028 m −3.
Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)
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Discount for regular customers! If the total of your purchases from the seller
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