DHS 15.1 - Option 16. Decisions Ryabushko AP

DHS 15.1 - Option 16. Decisions Ryabushko AP

1. Dana function u (M) = u (x, y, z) and the point M1, M2. Calculate: 1) The derivative of this function in the direction of the point M1 M1M2 vector; 2) grad u (M1)

1.16. u (M) = ln (x3 + y3 + z + 1), M1 (1, 3, 0), M2 (-4, 1, 3)

2. Calculate the surface integral of the first kind on the surface S, where S - part of the plane (p), cut off by the coordinate planes.

 (P): x - 2y + 2z = 2

3. Calculate the surface integral of the second kind.

 where S - the surface of the paraboloid z = x2 + y2 (normal vector n which forms an obtuse angle with the unit vector k), cut-off plane z = 4.

4. Calculate the flow vector field a (M) through the outer surface of the pyramid formed by plane (p) and the coordinate planes in two ways: a) determination using flow; b) using the formula Ostrogradskii - Gauss.

4.16. and (M) = 4zi + (x - y - z) j + (3y + z) k, (p): x - 2y + 2z = 2

Additional information:

Detailed solution. Designed in PDF format for easy viewing of IDZ solutions on smartphones and PCs. In MS Word (doc format) sent additionally.