DHS 15.1 - Option 3. Decisions Ryabushko AP

DHS 15.1 - Option 3. Decisions Ryabushko AP

1. Dana function u (M) = u (x, y, z) and the point M1, M2. Calculate: 1) The derivative of this function in the direction of the point M1 M1M2 vector; 2) grad u (M1)

1.3. u (M) = ln (x2 + y2 + z2), M1 (-1, 2, 1), M2 (3, 1, -1)

2. Calculate the surface integral of the first kind on the surface S, where S - part of the plane (p), cut off by the coordinate planes.

 (P): 3x + 3y + z = 3

3. Calculate the surface integral of the second kind.

 where S - the outer side surface of the cube bounded by the planes x = 0, y = 0, z = 0, x = 1, y = 1, z = 1

4. Calculate the flow vector field a (M) through the outer surface of the pyramid formed by plane (p) and the coordinate planes in two ways: a) determination using flow; b) using the formula Ostrogradskii - Gauss.

4.3. and (M) = xi + (x + z) j + (y + z) k, (p): 3x + 3y + z = 3

Additional information:

Detailed solution. Designed in PDF format for easy viewing of IDZ solutions on smartphones and PCs. In MS Word (doc format) sent additionally.

Discount for regular customers! If the total of your purchases from the seller Massimo86 exceeds:

• $30 discount 10%
• $20 discount 7%
• $18 discount 6%
• $15 discount 5%
• $12 discount 4%
• $9 discount 3%
• $6 discount 2%
• $3 discount 1%