Solution of problem 624 of the collection on general ch
- Price in currencies:
- 0.29 $ · 25 RUB · 0.26 €
- Category:
- Chemistry
- Item:
- 624_Glinka.jpg (67.01 KB)
- Uploaded:
- 20.05.2016 16:28:10
- Sales:
- 1
- Refunds:
- 0
- Seller:
- Михаил_Перович · about the seller and their products
DESCRIPTION
Solution of problem 624 of the collection on general ch
624. Write the equations for the half reactions of oxidation and reduction for the following reactions and determine in which cases hydrogen serves as an oxidizer and in which as a reducing agent:
A) 2Al + 6HCl = 2AlCl3 + 3H2
B) 2H2 + O2 = 2H2O
C) 2Na + 2H2O = NaOH + H2
D) BaH2 + 2H2O = Ba (OH) 2 + 2H2
REVIEWS
Reviews: (0)
No customer reviews yet.
DISCOUNTS
Discounts:
Discount for regular customers! If the total of your purchases from the seller Михаил_Перович exceeds:
- $200 discount 15%
- $100 discount 10%
- $50 discount 7%
- $20 discount 5%
- $10 discount 3%
- $5 discount 2%
- $1 discount 1%