Solution of the problem of the collection of Kep 5.5.12

Solution of the problem of the collection of Kep 5.5.12

Plate ABCD is fixed in a horizontal position by means of hinges and three rods 1, 2 and 3. The weight of the plate 10 G1 = H, the points A and D of the second plate is hinged plate width EF = AD weight and G2 = 8 N. Define force in Terminal 1, when the distance a = 0.4 m.

Additional information:

Immediately after payment you will receive a link to the zip file with the task 5.5.12 (Chapter 1 - statics topic - 5.5: Equilibrium spatial system of parallel forces) on the theoretical mechanics of collection of short tasks Kep OE, JA Viba, OP Grapis, JA Svetinysh and others. Publishing Moscow / Graduate School / 1989, 2009, 2012. The task is made in the format word (typed or hand-written decision in a Word) or in manuscript form in the format gif, packed to the archive zip (open on any PC) .After checking the solutions would be very grateful if you leave your positive feedback.