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Solving a problem in physics section 44 point 22 quantu
22. Determine the energy absorbed or released during a nuclear reaction 4420Ca + 11H → 4119K + 42He. Weights nuclei involved in the reactions: m (4420Ca) = 7,2992 • 10-26 kg, m (11H) = 1,6736 • 10-27 kg, m (4119K) = 6,8021 • 10-26 kg, m (42He) = 6,6467 • 10-27 kg
Detailed solution. Decorated in Microsoft Word 2003. (Target decided to use formula editor)
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