Task 20475.

Task 20475.

Diatomic gas at a pressure of 1200 kPa p1 = volume has V1 = 0,18 m ^ 3, at a pressure of 850 kPa p2 = - volume V2 = 0,42 m ^ 3. The transition from the first state to the second was done in two stages: first by the isotherm, and then isochor. The amount of heat absorbed by the gas Q, the increase of internal energy. To determine gas job A.

Additional information:

Detailed solution shorthand terms, formulas and laws used in the decision, the withdrawal of the calculation formula and the response.
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