Task 20306.

Task 20306.

Diatomic gas at a pressure of 440 kPa p1 = volume has V1 = 0,83 m ^ 3, at a pressure p2 = 120 kPa - volume V2 = 0,39 m ^ 3. The transition from the first state to the second was done in two stages: first by the isotherm, and then isochor. The amount of heat absorbed by the gas, Q, gas work A. Determine the increment of internal energy.

Additional information:

Detailed solution shorthand terms, formulas, laws used in the decision, the withdrawal of the calculation formula and the response.

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