Problem 10012.

Problem 10012.

The law of motion of a point along a curved section of the trajectory with a radius R = 1 m is expressed by the equation S = A Bt^2, where A = 8m, B = -2 m/s^2. Find: 1) at what point in time the normal acceleration an of the point is 9 m/s^2 and 2) what is the velocity V, tangential at and total a of the point´s acceleration at that point in time.

Additional information:

A detailed solution with a brief note of the conditions, formulas and laws used in the solution, the derivation of the calculation formula and the answer.